Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 10)
10.
A transformer with a 110 V primary has a 15:1 turns ratio. The load resistance, RL, is 120 
. What is the approximate voltage across the load?
. What is the approximate voltage across the load?Discussion:
53 comments Page 6 of 6.
Imran ali said:
7 years ago
It is so simple just use formula.
N1/N2=V1/V2.
then
put values
15/1=110/V2 (finding value of V2 we can write V2).
so on.
15= 110/V2 then cross multiplying.
V2=110/15,
V2=7.3v.
N1/N2=V1/V2.
then
put values
15/1=110/V2 (finding value of V2 we can write V2).
so on.
15= 110/V2 then cross multiplying.
V2=110/15,
V2=7.3v.
(2)
Pritul Panchal said:
7 years ago
Given Data:
1. Primary Voltage: 110V.
2. Turns ratio: 15:1 (15=Primary turns, 1=Secondary Turns).
V1/V2 = N1/N2.
110/V2 = 15/1.
110*1/ 15 = V2.
Hence V2 = 7.3V across transformer secondary winding.
Now, load is of 120Ohm connected across the secondary winding.
So, the load will face the same secondary voltage.
1. Primary Voltage: 110V.
2. Turns ratio: 15:1 (15=Primary turns, 1=Secondary Turns).
V1/V2 = N1/N2.
110/V2 = 15/1.
110*1/ 15 = V2.
Hence V2 = 7.3V across transformer secondary winding.
Now, load is of 120Ohm connected across the secondary winding.
So, the load will face the same secondary voltage.
(9)
Guna said:
7 years ago
In the transformer,
The Turns ratio means N1/N2.
And transformation ratio Means = N2/N1 = k.
So, that N1/N2 = 1/15.
The Turns ratio means N1/N2.
And transformation ratio Means = N2/N1 = k.
So, that N1/N2 = 1/15.
(3)
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