Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 16)
16.
A 12 k
resistor, a 15 k resistor, and a 22 k resistor are in series with two 10 k resistors that are in parallel. The source voltage is 75 V. Current through the 15 k resistor is approximately
resistor, a 15 k resistor, and a 22 k resistor are in series with two 10 k resistors that are in parallel. The source voltage is 75 V. Current through the 15 k resistor is approximatelyDiscussion:
16 comments Page 2 of 2.
SANDEEP K PATIL said:
8 years ago
@Thejasvi.
How can you say 5ma is correct?
The current through circuit is 1.4ma and through 15k resistor is also the same because it is connected in series, for your kind information voltage across 15k resistor is not 75 volts. it varies in series circuit.
How can you say 5ma is correct?
The current through circuit is 1.4ma and through 15k resistor is also the same because it is connected in series, for your kind information voltage across 15k resistor is not 75 volts. it varies in series circuit.
Fatima said:
7 years ago
5 mamp.
Priya said:
7 years ago
1.39 mA.
Aniket kumbhar said:
7 years ago
Please explain the answer clearly.
HAris ShAikh said:
6 years ago
R = 12+15+22 = 49kohm.
R = 10/2 = 5kohm.
TR = 49+5 = 54kohm = 54000 ohm.
V = 75V.
I = V/R.
I = 75/54000 = 1.38mA.
R = 10/2 = 5kohm.
TR = 49+5 = 54kohm = 54000 ohm.
V = 75V.
I = V/R.
I = 75/54000 = 1.38mA.
Asamare said:
8 months ago
The source voltage 75v in the circuit.
VT = 75v
15krI = ?
IT = ?
The circuit is both series and parallel but total voltage is given.
R15kI = VT/R15k.
R15kI = 75/15000,
= 5mA.
VT = 75v
15krI = ?
IT = ?
The circuit is both series and parallel but total voltage is given.
R15kI = VT/R15k.
R15kI = 75/15000,
= 5mA.
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