Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 21)
21.
A voltage divider consists of two 100 k
resistors and a 12 V source. What will the output voltage be if a load resistor of 1 M
is connected to the output?


Discussion:
24 comments Page 3 of 3.
Henry said:
1 decade ago
Vt=12v, Rt=200k (from R1(100K)+R2(100K)), we can get It=0.00006amps.
Solving for Vout, Vout= It x R'.
R' = (100K)(1M)/(100K)+(1M) = 90909.09091 ohms.
so, Vout = (0.00006)x(90909.09091) = 5.45 volts.
Answer: Option D: 5.7volts.
Solving for Vout, Vout= It x R'.
R' = (100K)(1M)/(100K)+(1M) = 90909.09091 ohms.
so, Vout = (0.00006)x(90909.09091) = 5.45 volts.
Answer: Option D: 5.7volts.
CPREDDY said:
1 decade ago
R1=100K,R2=100K,R3=1000K
HERE R1,R2 ARE IN SERIES WITH 12V.
AND R2,R3 ARE PARALLEL
VOUT=12*(100||1000)/(100+100||1000)=120/21=5.7
HERE R1,R2 ARE IN SERIES WITH 12V.
AND R2,R3 ARE PARALLEL
VOUT=12*(100||1000)/(100+100||1000)=120/21=5.7
Anand said:
1 decade ago
@Rohit can you explain about the answer.
Rohit said:
1 decade ago
The above method is wrong.
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