Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 21)
21.
A voltage divider consists of two 100 k
resistors and a 12 V source. What will the output voltage be if a load resistor of 1 M is connected to the output?
resistors and a 12 V source. What will the output voltage be if a load resistor of 1 M is connected to the output?Discussion:
24 comments Page 3 of 3.
Raja Tayyab said:
5 years ago
Let me explain clearly in simple words. Firstly the circuit was 2 100k resistors in series and 12V source. Then a load resistor of 1M was added and load is always added in parallel to the source. This 1M will be parallel to one 100k. So the circuit becomes:
R1+ (R2||R3)= 100k+ (100k||1000K),
The voltage will be divided in 100k and 100k||1000k. So applying VDR at load.
100k||1000k=90k,
Vo = 12*[(90k)/(90k+100k)] = 5.7V.
R1+ (R2||R3)= 100k+ (100k||1000K),
The voltage will be divided in 100k and 100k||1000k. So applying VDR at load.
100k||1000k=90k,
Vo = 12*[(90k)/(90k+100k)] = 5.7V.
(7)
Kvnblz said:
3 years ago
By approximation method.
Vb = 12(100/200) = 6 V.
Assuming Germanium transistor,
Vb = 0.3 + Vo, thus Vo = 6-0.3 = 5.7V.
Vb = 12(100/200) = 6 V.
Assuming Germanium transistor,
Vb = 0.3 + Vo, thus Vo = 6-0.3 = 5.7V.
(1)
Geeta H said:
3 years ago
@Jeyaraj
The vdr formula is;
Vout = R2 * Vin/(R1+R2).
Then you will get 5.7 as the answer.
So, here D is the right answer.
The vdr formula is;
Vout = R2 * Vin/(R1+R2).
Then you will get 5.7 as the answer.
So, here D is the right answer.
(1)
Subodh said:
3 years ago
Can anybody explain it properly?
(1)
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