Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 21)
21.
A voltage divider consists of two 100 k
resistors and a 12 V source. What will the output voltage be if a load resistor of 1 M is connected to the output?
resistors and a 12 V source. What will the output voltage be if a load resistor of 1 M is connected to the output?Discussion:
24 comments Page 2 of 3.
Santosh said:
9 years ago
The voltage will divide in series where the current is in parallel. In question indicated a voltage divider rule so resistors also in series.
CPREDDY said:
1 decade ago
R1=100K,R2=100K,R3=1000K
HERE R1,R2 ARE IN SERIES WITH 12V.
AND R2,R3 ARE PARALLEL
VOUT=12*(100||1000)/(100+100||1000)=120/21=5.7
HERE R1,R2 ARE IN SERIES WITH 12V.
AND R2,R3 ARE PARALLEL
VOUT=12*(100||1000)/(100+100||1000)=120/21=5.7
Geeta H said:
3 years ago
@Jeyaraj
The vdr formula is;
Vout = R2 * Vin/(R1+R2).
Then you will get 5.7 as the answer.
So, here D is the right answer.
The vdr formula is;
Vout = R2 * Vin/(R1+R2).
Then you will get 5.7 as the answer.
So, here D is the right answer.
(1)
Kvnblz said:
3 years ago
By approximation method.
Vb = 12(100/200) = 6 V.
Assuming Germanium transistor,
Vb = 0.3 + Vo, thus Vo = 6-0.3 = 5.7V.
Vb = 12(100/200) = 6 V.
Assuming Germanium transistor,
Vb = 0.3 + Vo, thus Vo = 6-0.3 = 5.7V.
(1)
Pranjal singh said:
9 years ago
But it's not given in the question that resistance is series or parallel. Then how to solve this.
Uduak Ekanem said:
1 decade ago
But it is not stated in the question if the resistors are connected in series or parallel.
Dayanand said:
8 years ago
They have not mentioned that 1M ohm is in parallel.
Then, how did you solve?
Then, how did you solve?
Archana said:
1 decade ago
But it has not said that o/p resistance parallel with one of 100k resistor.
(1)
Maya said:
1 decade ago
One 100k and 1M are in parallel and other one is in series then apply VDR.
Shoji said:
1 decade ago
Explanation by @Cpreddy seems to be correct approach to the problem.
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