Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 13)
13.
When a load resistance is removed from the output of a voltage divider circuit, the current drawn from the source
Discussion:
20 comments Page 2 of 2.
Niharika said:
1 decade ago
Shouldn't it remain same as the other resistor will be present Because as per the v/g divider circuit I suppose there must be more than a resistor?
Arun said:
1 decade ago
Electrical Source in always infinite. Load cannot alter the source current. Current remains the same. But only the drop matters.
Mohan said:
1 decade ago
For example use a variable resistor and decrease range of resistor value. Now the source current would decrease.
Geeta H said:
3 years ago
In an voltage divider circuit, for no-load, it is called an open circuit hence current decreases.
(1)
Suraj said:
6 years ago
@Nivi.
Because the circuit is not open-circuited.
Maybe, The circuit is short-circuited.
Because the circuit is not open-circuited.
Maybe, The circuit is short-circuited.
NIVI said:
1 decade ago
If circuit is open then current is not flowing in the ckt, then why not its answer is D?
SHOBHAN NAYAK said:
4 years ago
I'm agree @Noxa.
My explanation is; If load removes means current increase.
My explanation is; If load removes means current increase.
Sudheer said:
9 years ago
IN SC "I" high, "V" low.
IN OC "I" low, "V" high. It's inverse notation.
IN OC "I" low, "V" high. It's inverse notation.
Santy said:
1 decade ago
In voltage divider circuit the load is connected across a resistor.
Ankit Tiwari said:
1 decade ago
Why option D is not correct please tell me with explanation?
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