Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 15)
15.
The parallel combination of a 470 
resistor and a 680 resistor is in series with the parallel combination of four 2 k resistors. The total resistance is
resistor and a 680 resistor is in series with the parallel combination of four 2 k resistors. The total resistance is1,650
1,078
77.8
778
Discussion:
15 comments Page 2 of 2.
Chaithra said:
9 years ago
I got the second step easily from your explanation. Thank you @Sandeep.
Riya said:
7 years ago
First parallel combination 470 and 680 is 2779.1.
Not 277.91.
Correct me, if I am wrong.
Not 277.91.
Correct me, if I am wrong.
Mujib said:
5 years ago
@Riya,
Solving first parallel combination becomes 277.91.
Because R1 multiply by R2 divide by R1+R2.
470 * 680/470 + 680 = 319600/1150 = 277.913.
Solving first parallel combination becomes 277.91.
Because R1 multiply by R2 divide by R1+R2.
470 * 680/470 + 680 = 319600/1150 = 277.913.
Vanuja mohan said:
4 years ago
277 is the right answer.
Koffi Agbenokoudji said:
2 months ago
Here, the question is about two parallel circuits, and the word series refers to a line that connects them.
So the answer is = 778 ohms.
Use this method:
(1/470+1/680) + (1/2+1/2+1/2+1/2) with this method, it will give us [778 ohms] as the correct answer.
So the answer is = 778 ohms.
Use this method:
(1/470+1/680) + (1/2+1/2+1/2+1/2) with this method, it will give us [778 ohms] as the correct answer.
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