Electrical Engineering - Series Circuits - Discussion

Discussion Forum : Series Circuits - General Questions (Q.No. 4)

Series Circuits

A certain series circuit consists of a 1/8 W resistor, a 1/4 W resistor, and a 1/2 W resistor. The total resistance is 1200

. If each resistor is operating in the circuit at its maximum power dissipation, total current flow is

27 mA

2.7 mA

19 mA

190 mA

Answer: Option

Explanation:

Total P = P1 + P2 + P3 = 7/8w.

P = I²R.

I = sqrt (P/R)

Now, P = 7/8w, R = 1200 ohm.

Therefore,

I= sqrt ( (7/8)/1200 ) = 0.0270030862 = 27 mA.

Discussion:

32 comments Page 2 of 4.

Megharaj said: 8 years ago

How to calculate sqrt (7/8) /1200 without calculator? Anybody, please tell me.

Jay chhalaliya said: 1 decade ago

But in parallel circuit formula of total power.

1/P = 1/P1+1/P2+1/P3.

Punith said: 10 years ago

How to calculate sqrt (7/8)/1200 without calculator anybody please?

Susanta said: 9 years ago

When power are series it calculate as equivalent capacitance.

Chaman chauhan said: 8 years ago

How it come sqrt of (7/8)/1200= 0.027003?

Please describe.

Subhash said: 7 years ago

How it come √(7/8)/1200= 0.027003?

Please describe.

Thanushree said: 1 decade ago

I can't understood this problem please explain.

Vishal said: 9 years ago

Same doubt for me also, anybody tell me please.

Jagan said: 9 years ago

Actually, the parallel circuit formula is 1/p.

Vipin said: 7 years ago

Please explain the last step of this answer.

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