Electrical Engineering - Series Circuits - Discussion

Discussion Forum : Series Circuits - General Questions (Q.No. 5)
5.
Which of the following series combinations dissipates the most power when connected across a 120 V source?
one 220 resistor
two 220 resistors
three 220 resistors
four 220 resistors
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
44 comments Page 3 of 5.

Krish said:   1 decade ago
Resistor is a device which resists the flow of power through it, The answer will be chosen from the least value of the options simple.

Sadik pasha said:   1 decade ago
In series, number of resistors increase total resistance increase so resistance increase current decrease so power dessipation less.

Dilip said:   1 decade ago
Power = v*2/r.

If r is minimum then power has maximum value.
And we know that i = v/r.

And p = i^2*r directionally proportional.

Sriksnth said:   1 decade ago
P = v^2/r.

Power is inversely proportionally to resistance. So, as resistance is less power will be more.

Option A is correct.

Hemraj said:   1 decade ago
In this case

P=i^2*r power dissipation is perportional to the ressitace. So more resistace causes of more power dissipation.

Mairaj Alam said:   6 years ago
Keeping voltage constant power is inversely proportional to resistance, so resistance increases power decrease.
(1)

Apiaps said:   10 years ago
v = IR = I = V/R as are reduces I increases.

And P = I^2 *R.

As R reduces I increases as p increases.

Binay said:   1 decade ago
As p = v^2/r, here v constant, So pr = constant.

So for max p, r should minimum.

Amarnath Maity said:   8 years ago
P = V^2/R.

Choose the lowest total resistance to maximize the dissipation.
(2)

Ponjothirajalingam said:   1 decade ago
But at the same time Power is directly proportional to resistance only.


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