Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 5)
5.
Which of the following series combinations dissipates the most power when connected across a 120 V source?
one 220 
resistor
resistortwo 220 resistors
resistorsthree 220 resistors
resistorsfour 220 resistors
resistorsDiscussion:
44 comments Page 2 of 5.
SHAMIK said:
10 years ago
P = V^2/R.
As R increases, P decreases.
As R increases, P decreases.
RAMESH said:
9 years ago
Nice explination @Sadik Pasha.
Jayaram said:
9 years ago
Nice explanation, Thank you all.
Susanta said:
9 years ago
When power are series it calculated as parallel so, many numbers resistor has the power are too low then the single 1/p1 + 1/p2 + 1/p3 ...< p1.
Vijay said:
9 years ago
Nice @Lavanya.
Angesh said:
8 years ago
Why p=i^2*r is not considered?
Shambhavi said:
8 years ago
P=i^2 R i.e., P=V^2/R.
So if the resistance goes on decreasing, the corresponding power is less. So the minimum resistance i.e.,220 ohm delivers more power.
So if the resistance goes on decreasing, the corresponding power is less. So the minimum resistance i.e.,220 ohm delivers more power.
Syed said:
8 years ago
Clear explanation, thank you @Satyaranjan Acharya.
Ajith kumar A said:
8 years ago
P is inversely proportion to R.
Jay chandra said:
8 years ago
Nice @Lavanya.
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