Electrical Engineering - Series Circuits - Discussion

Discussion Forum : Series Circuits - General Questions (Q.No. 6)
6.
When one of three series resistors is removed from a circuit and the circuit is reconnected, the current
increases
increases by one-third
decreases by one-third
decreases by the amount of current through the removed resistor
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
30 comments Page 3 of 3.

Pooja said:   1 decade ago
Resistance oppose the flow of current if one opposition resistance is remove so obviously current increase.

Sam said:   1 decade ago
Hello friends,

In series circuit current remains the same. Even you have high resistance or low resistance because current is constant in series connection.

Rohan said:   1 decade ago
i1 = 1/3r.
i2 = 1/2r.

i2 = 3/2(i1).

So current increases by 1.5 not by 1/3.

Bharath said:   1 decade ago
As the 3 resistances are connected in series the total resistance is the sum of the 3 resistances. As one of the resistance is removed the total resistance will be lesser than this. Since the current is i=v/r the current will be greater than the original current.

Kiran said:   1 decade ago
Why not current increases by one third?

Ashish kumar mishra said:   1 decade ago
By the ohms low wn khow that:

V=IR.

Then,

Current (I) =V/R.

Resistance (R) =V/I.

By the above explanation we can easily see that the resistance is inversely proportional to the current. So when the no.of resistance decrease the current will increase.

Style seva said:   1 decade ago
V=IR.

R=V/I.

So resistor and current inversely proportional. So resistor value decreases means the current value is to be increased.

Anand said:   1 decade ago
Nice explanation pooms

LAVANYA said:   1 decade ago
AS PER OHMS LAW... I=V/R..

Pooms said:   1 decade ago
When resistance decreases,the current increases.Because R=V/I, resistance and current are inversely proportional.


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