Electrical Engineering - Series Circuits - Discussion

Discussion Forum : Series Circuits - General Questions (Q.No. 6)
6.
When one of three series resistors is removed from a circuit and the circuit is reconnected, the current
increases
increases by one-third
decreases by one-third
decreases by the amount of current through the removed resistor
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
30 comments Page 2 of 3.

Rupesh said:   1 decade ago
As the values of resistors are not given so we can say current will increase only.

Srikanth said:   1 decade ago
We know I = v/r.

Current and resistance are inversely proportional.

So as resistance decreases I increases.

Option A is correct.

Vandana said:   1 decade ago
Current is always same in all resistors in series combination.

Praveen reddy said:   1 decade ago
Current limiting resistors can limit the small current here not considered current same in series circuit.

Praveen said:   1 decade ago
When one resistor is removed the current will be increased by 1/6, hence there is no option of that option A is correct.

Mybelli sk said:   10 years ago
Based on ohms law R = V/I.

I = V/R that's enough.

Satishkumar said:   10 years ago
Ya I agree with the answer @Bharat.

Gitanjali said:   9 years ago
Here wrong options are given, as we know in series network current is always same.

Akash Mohan said:   9 years ago
In series circuit current is always same.

Elsadig Elmahdi Elsharif said:   9 years ago
That is why I am amazed.

In series circuit current is always same. But according to Ohm Law, it increases and decreases proportionally to the resistors.

As no option for steady current is given. So, the answer A is the most right one.


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