Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 1)
1.
A 10 
resistor, a 90 mH coil, and a 0.015 
F capacitor are in series across an ac source. The impedance magnitude at 1,200 Hz below fr is
resistor, a 90 mH coil, and a 0.015 F capacitor are in series across an ac source. The impedance magnitude at 1,200 Hz below fr is1,616
161
3,387
1,771
Discussion:
28 comments Page 2 of 3.
AGGREY KERE said:
1 decade ago
From R-L-C circuit above, we know that; Z=root of R^2+(XL-XC)^2.
but XL=2pi*fr*L.
XC=1/2Pi*fr*C.
but XL=2pi*fr*L.
XC=1/2Pi*fr*C.
ROBERT said:
1 decade ago
XL=2*3.14*F*L THIS IS THE FORMAL.
I WAS ASK TO MAKE SO I CAN FIND UNKNOWN F AND L.
MOVE THING AROUND I CAME UP WITH SO ARE THESE RIGHT.
F=2*PI*L*XL.
L=2*PI*F*XL.
I WAS ASK TO MAKE SO I CAN FIND UNKNOWN F AND L.
MOVE THING AROUND I CAME UP WITH SO ARE THESE RIGHT.
F=2*PI*L*XL.
L=2*PI*F*XL.
Prashant said:
10 years ago
I think result is not coming from above all formula I want real answer from you friends please reply.
Shwetha said:
9 years ago
Its (xl-xc). Because xl is greater than xc.
Rajat Dey said:
9 years ago
I know above formula but this is very long process and heavy time span. So how can do it quickly? Please help me.
Shailu said:
9 years ago
Is it correct? Above explained examples?
Dinesh said:
8 years ago
Quicker method needed.
Puja said:
8 years ago
Yes, I agree @Prashant.
Siddu bhandarkavathe said:
7 years ago
It is 1/2 π √ LC.
Hassan said:
6 years ago
How we can change the units?
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