Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 1)
1.
A 10 
resistor, a 90 mH coil, and a 0.015 
F capacitor are in series across an ac source. The impedance magnitude at 1,200 Hz below fr is
resistor, a 90 mH coil, and a 0.015 F capacitor are in series across an ac source. The impedance magnitude at 1,200 Hz below fr is1,616
161
3,387
1,771
Discussion:
25 comments Page 2 of 3.
Rajat Dey said:
8 years ago
I know above formula but this is very long process and heavy time span. So how can do it quickly? Please help me.
Shwetha said:
8 years ago
Its (xl-xc). Because xl is greater than xc.
Prashant said:
8 years ago
I think result is not coming from above all formula I want real answer from you friends please reply.
ROBERT said:
8 years ago
XL=2*3.14*F*L THIS IS THE FORMAL.
I WAS ASK TO MAKE SO I CAN FIND UNKNOWN F AND L.
MOVE THING AROUND I CAME UP WITH SO ARE THESE RIGHT.
F=2*PI*L*XL.
L=2*PI*F*XL.
I WAS ASK TO MAKE SO I CAN FIND UNKNOWN F AND L.
MOVE THING AROUND I CAME UP WITH SO ARE THESE RIGHT.
F=2*PI*L*XL.
L=2*PI*F*XL.
AGGREY KERE said:
9 years ago
From R-L-C circuit above, we know that; Z=root of R^2+(XL-XC)^2.
but XL=2pi*fr*L.
XC=1/2Pi*fr*C.
but XL=2pi*fr*L.
XC=1/2Pi*fr*C.
Manindra said:
9 years ago
Fr = 1/2*pi*sqrt(L*c)=4331.648.
f = fr-1200Hz = 3131.64.
Xl = Wl = 2*3.14*3131.64*l.
Xc = 1/wc.
Z = sqrt of(R^2+(XL-XC)^2) = 1616 ohm.
f = fr-1200Hz = 3131.64.
Xl = Wl = 2*3.14*3131.64*l.
Xc = 1/wc.
Z = sqrt of(R^2+(XL-XC)^2) = 1616 ohm.
DURAI said:
9 years ago
fr = 1/2*pi*sqrt (L*c).
Babu said:
9 years ago
We know that,
Resonance frequency:
Fr = 1/2*pi*sqrt(L*C).
Xl = Wl = 2*3.14*f*l.
Xc = 1/wc.
Resonance frequency:
Fr = 1/2*pi*sqrt(L*C).
Xl = Wl = 2*3.14*f*l.
Xc = 1/wc.
Mrakovic said:
9 years ago
fr = 1/2*pi*sqrt of LC.
fr = 4331.648.
f = fr-1200Hz=3131.64.
Z = sqrt of(R^2+(XL-XC)^2).
Z = 1617 ohm.
fr = 4331.648.
f = fr-1200Hz=3131.64.
Z = sqrt of(R^2+(XL-XC)^2).
Z = 1617 ohm.
Rahul mishra said:
10 years ago
IN RLC SERIES CIRCUITS WE KNOW:
Z = (jw)^2+(jw)R/L+1/LC.
Z = (jw)^2+(jw)R/L+1/LC.
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