Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 1)
1.
An ammeter has an internal resistance of 50 
. The meter movement itself can handle up to 1 mA. If 10 mA is applied to the meter, the shunt resistor, RSH1, is approximately
. The meter movement itself can handle up to 1 mA. If 10 mA is applied to the meter, the shunt resistor, RSH1, is approximately55
5.5
50
9
Discussion:
16 comments Page 2 of 2.
Muna said:
1 decade ago
The resistance is calculated by voltage equtation.
R = 50*1/1000*1000/9 = 5.5ohm.
R = 50*1/1000*1000/9 = 5.5ohm.
Hemanth said:
6 years ago
The resistance is calculated by voltage equtation.
R = 50*1/1000*1000/9 = 5.5ohm.
R = 50*1/1000*1000/9 = 5.5ohm.
(2)
Anand said:
1 decade ago
Can anybody explain the answer ?
David said:
8 years ago
Good explanation @Sumant.
Sharan said:
8 years ago
Well explained @Sumant.
Dushyant Dutta said:
1 decade ago
Rg*Ig/I-Ig=S
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