Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 14)
14.
If you wish to increase the amount of current in a resistor from 120 mA to 160 mA by changing the 24 V source, what should the new voltage setting be?
Discussion:
33 comments Page 4 of 4.
MANI said:
1 decade ago
1ST INCREASING THE AMOUNT OF CURRENT FROM 120mA THEN CHANGING THE VOLTAGE FROM 24V.. K SO, R=V/I R=24/120 R=0.2K.O ... NOW WE R FIND RESISTOR VALUE... NOW WE WANT NEW VOLTAGE SETTING... SO,PUT THE RESISTOR VALUE IN OHMS LAW... ALREADY WE HAVE mA VALUE.. SO, V=I*R V=160*0.2 "V=32V "...
Raghu said:
1 decade ago
For 1v 5ma changed so like that 40 ma changes means 8 v changes.
So to add that 24+8=32v for 160A
So to add that 24+8=32v for 160A
Ajith128 said:
1 decade ago
No need to go for calculation 4 like these maths. We know only option to increase current in a give circuit increase voltage. So to increase current voltage must be increased. All other values are less the 24 and only 32 and 320 are higher.
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