Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 14)
14.
If you wish to increase the amount of current in a resistor from 120 mA to 160 mA by changing the 24 V source, what should the new voltage setting be?
Discussion:
33 comments Page 3 of 4.
Sunil said:
9 years ago
120 : 160 : 24 : x.
x = 160 * 24/120,
x = 32.
x = 160 * 24/120,
x = 32.
Vaidya Preet said:
6 years ago
Thank You for the explanation of the answer.
Jake said:
7 years ago
Thanks @Mani.
The resistance is constant.
The resistance is constant.
Pooms said:
1 decade ago
Thank you Mr.Mani...... I'm very clear....
Shahid ansari said:
8 years ago
Good trick, thank you @Ashutosh Sharma.
Sibananda chakra said:
1 decade ago
Thank you all of you. I am very clear.
M.srav said:
9 years ago
Thank you all for giving me an idea.
Swetha said:
7 years ago
Ohm's law applies.
V1/V2=I1/I2.
V1/V2=I1/I2.
(1)
Suri said:
9 years ago
Logically you are right @Raghu.
Krunal soni said:
8 years ago
Nice trick, Thaks @Ashutosh.
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