Electrical Engineering - Inductors - Discussion

Discussion Forum : Inductors - General Questions (Q.No. 18)
18.
A switch, a 220 resistor, and a 60 mH inductor are in series across a 20 V battery. What is the current through the inductor two time constants after the switch is closed?
91 mA
78 mA
57 mA
400 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 2 of 2.

Sumeet said:   1 decade ago
In a RL circuit V=v(1-e^-t*R/L) as t = 2*L/R

So e^-2*L/R*R/L would be e^-2 as a result V = .86*v.

So current i =V/R i.e. 86*20/220 = 78 ma(approx.)


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