Electrical Engineering - Inductors - Discussion

Its simple question. When the pointer inducts 0 means the current goes to infinite value its happens only when the circuit s shorted (rejection of load and its shorted).

Ans:C.(shorted)
if the inductor is shorted, inductor will offers zero impedance to current hence the current will not pass through the ohmmeter which has a resistance in it.hence the pointer will not operate at that condition

Impedance inductor inductance reactance different please.

An ohmmeter measures resistance, not impedance. An inductor is just a length of wire wound around a coil. At DC the resistance will be zero for an ideal inductor or very low for a real inductor. So you can't tell if this is a short or a high-q inductor. Suppose I measure a wire that is 1 foot long and it measures zero Ohms. Then I make 1 turn to make and inductor. The ohmmeter will still measure the same. So you can't tell if it is a good inductor or shorted one.

This statement from @Humar above is entirely wrong:

"If the inductor is shorted, inductor will offers zero impedance to current hence the current will not pass through the ohmmeter which has a resistance in it. Hence the pointer will not operate at that condition".

The truth is this:

If the inductor is shorted, inductor will offer zero impedance to current hence AS MUCH CURRENT AS POSSIBLE will flow through the ohmmeter, indicating the that the resistance is zero.

Zero impedance means maximum current not minimum current.

If inductor is ideal ohm meter indicate zero reading. Or inductor is shorted.

Of course ohmeter read zero. But it is impossible as every conductor has resistance. So we could say it is ideal inductor.

If the inductor is shorted, inductor will offers zero impedance to current hence the current will not pass through the ohmmeter which has a resistance in it. Hence the pointer will not operate at that condition.

When it is opened what happend?

If the inductor is shorted, inductor will offers zero impedance to current hence the current will not pass through the ohmmeter which has a resistance in it. Hence the pointer will not operate at that condition.