Electrical Engineering - Energy and Power - Discussion

Discussion Forum : Energy and Power - General Questions (Q.No. 7)
7.
A 15 V source is connected across a 12 resistor. How much energy is used in three minutes?
938 Wh
0.938 Wh
56.25 Wh
5.6 Wh
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
31 comments Page 2 of 4.

Tejswee said:   1 decade ago
Energy = Power*Time = (i^2*r)*(3/60) = 0.9375
(1)

Pratap sahu said:   1 decade ago
Let
V = 15, R = 12.
So I = V/R = 15/12 = 1.25 A.

And P=V*I, So P = 15*1.25 = 18.75wh.

In 1 hour power will consume 18.75wh.
In 1 minute power will consume = 18.75/60 = 0.3125wh.
In 3 minute power will consume = 0.3125*3 = 0.9375wh.

Naresh Jadav said:   1 decade ago
Let,

3 minite = 0.05h.

I = V/R.

=15/12 = 1.25 A.

Power = V*I = 12*1.25 = 18.75w.

Now,

W*h = 18.75*0.05 = 0.9375wh.

Anonymous said:   1 decade ago
Why can't we use the formula V^2/R*t?

Mrakovic said:   1 decade ago
W = U^2/R.

W = 225/12 = 18.75W.

3 min = 0.05h.

Wh = W*t = 18.75*0.05 = 0.9375Wh.

BIPRADAS GHOSH said:   1 decade ago
Energy = (I)2Rt.

I = V/R = 15/12 = 1.25.

R = 12 and t = 3 min = 3/60 hr = 0.05 hr.

So, Energy = (1.25)2*12*0.05 = 0.9375.

Mohamed Basha j said:   1 decade ago
P = V^2 / R , so P= 15^2*12 p = 18.75watts.

For 3 min = 3/60 = .05.

Used Energy = 18.75 * .05.

= 0.9375 Wh.

Answer = option B.

Hazrat Bilal Safi said:   1 decade ago
@Aramuthan. You are wrong.

P = IV;
I = V/R;

Since,
I = 15/12.
I = 1.25A.
P = 1.25*15 = 18.75.

3 minute= 3/60 hours = 0.05h.
Energy= 18.75* 0.05= 0.9375Wh.

Naser said:   1 decade ago
15*15/12 = 18.75.
18.75/60 = 0.3125.
0.3125*3 = 0.9375 wh.

Pankaj R.Patil said:   1 decade ago
v^2/r*t, t in hours.


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