Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 1)
1.
A 33
half-watt resistor and a 330
half-watt resistor are connected across a 12 V source. Which one(s) will overheat?


Discussion:
58 comments Page 4 of 6.
Swetha said:
7 years ago
The Key point is;
Less resistance value resistor will dissipate more heat.
The connection is a parallel circuit.
Formulae is Power = V*V/R.
Less resistance value resistor will dissipate more heat.
The connection is a parallel circuit.
Formulae is Power = V*V/R.
Akhil said:
1 decade ago
It should be "B" because in both resisters power is same i.e, 0.5 w.
So 330 R will have high power loss i^2*r than the 33 R.
So 330 R will have high power loss i^2*r than the 33 R.
Sana sahithi said:
1 decade ago
In both the resistors power dissipated is same.
Calculate currents and power in both resistors. Numerically they are equal.
Calculate currents and power in both resistors. Numerically they are equal.
Sonu kumar said:
9 years ago
Because both the resistor has equal rating and heating of resistor depends on wattage only. Not on the type of connection.
MANIKONDA MALAKONDAIAH said:
1 decade ago
As per the given question both are equal wattage so given two resistors never get over heated. So the answer is option D.
Stuti kushwaha said:
10 years ago
Option A should be correct according to i^2r we see that more current flow through 33 ohm. So more heat should across it.
Vinny said:
7 years ago
In question, if both resistors are connected in series across 12v supply, then answer is D, either the A correct answer.
Marshall said:
10 years ago
Both load are resistive components. It dissipate power. For sure both of them will produce heat. So both of them.
Subhrajit jena said:
8 years ago
According to power loss formula, 330 ohm resistor will produce overheating because both are connected in series.
S K Pillai said:
9 years ago
Question should be more clear. Whether the resistances are in series or in parallel? The answer differs D or A.
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