Electrical Engineering - Branch, Loop and Node Analyses - Discussion
Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 6)
6.
What is the voltage drop across R1?
Discussion:
21 comments Page 2 of 3.
Eee'ngineer said:
1 decade ago
The answer is 7.82 (approx). Tried with both nodal analysis and superposition theorem.
Ashiwani kumar said:
1 decade ago
Voltage drop across R1 = (12-Va).
Va = 4.18.
So VR1 = (12-4.18) = 7.82.
Va = 4.18.
So VR1 = (12-4.18) = 7.82.
Nouman said:
1 decade ago
First Calculate IR1:
IR1 is 0.1148 A.
R1 = 68 ohms.
Vr1 = Ir1 x R1 = 0.1148 x 68 = 7.8 V.
The answer is 7.8 V.
IR1 is 0.1148 A.
R1 = 68 ohms.
Vr1 = Ir1 x R1 = 0.1148 x 68 = 7.8 V.
The answer is 7.8 V.
Allen c. said:
1 decade ago
The answer is ~7.82V (12-4.18). Use Kirchhoff's Current Law (KCL).
Uttam gupta said:
1 decade ago
@Siddhartha.
x is what's value and 14 comes from where please explain it?
x is what's value and 14 comes from where please explain it?
Siddhartha said:
1 decade ago
Applying super position theorems and by solving them expression can be obtained i.e.,
((x-12)/68)=((x-14)/90).
On solving above expression we get x value as 3.67v.
Voltage drop is v1-x
i.e., 12-3.67=8.33v.
((x-12)/68)=((x-14)/90).
On solving above expression we get x value as 3.67v.
Voltage drop is v1-x
i.e., 12-3.67=8.33v.
Nabeel Hayat said:
1 decade ago
There are two loop, You have to find Loop 1 Current, using KVL, but as on resistor 37Ohm both current I1 and I2 are passing, so we also have to find Current I2,
For that we have to use KVL on both the loops, we have two equations, from that You can find I1,
After that,
V=IR.
V=I (68).
For that we have to use KVL on both the loops, we have two equations, from that You can find I1,
After that,
V=IR.
V=I (68).
Archana said:
1 decade ago
How to solve this problem to get the answer?
Tom said:
1 decade ago
Use with Kirchhoff Loop
105*I1 + 37*I2 = 12V
37*I1 +127*I2 = 4V
=> I1 & I2 ...
105*I1 + 37*I2 = 12V
37*I1 +127*I2 = 4V
=> I1 & I2 ...
Valentin said:
1 decade ago
The correct answer is 4,18~4.19V. To solve this problem is used the overlapping effects.
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