Digital Electronics - Counters - Discussion
Discussion Forum : Counters - General Questions (Q.No. 1)
1.
How many flip-flops are required to make a MOD-32 binary counter?
Discussion:
26 comments Page 3 of 3.
Daniel said:
8 years ago
What is the least number of jk flip flops it would take to create a mod 500 counter?
N.kiranmai said:
7 years ago
The formula is 2^p where p is the no of flip flops are used here we have to find the no of flip flops so 2^5 =32.
Piyush Kumar said:
6 years ago
Here, The minimum no of flip flops required for MOD 32 counter is 5.
But with 6 flip flop, we can also count 32 states. So I think n>=5. With 6 flip flop, we can represent 2^6 states, but if in this by some combinational circuits we can make it MOD 32 counter.
But with 6 flip flop, we can also count 32 states. So I think n>=5. With 6 flip flop, we can represent 2^6 states, but if in this by some combinational circuits we can make it MOD 32 counter.
(1)
Faisal yusuf said:
5 years ago
One flip flop store 1 bit 32 =100000 6 binary bit.
So, 6 flipflop use.
So, 6 flipflop use.
RISHI NIGAM said:
3 years ago
Yes, 2^n = 32 from where we get the answer is 5 is a generalized way of getting no of flip-flops and remember id mod is in between means not multiple of 2.
So we just higher 2 multiple for example 14 then we take 4 flipflops as we take count as 16.
So we just higher 2 multiple for example 14 then we take 4 flipflops as we take count as 16.
Komal jadhav said:
2 years ago
How many flip flops are required to design the mod 29 counter? Please explain to me.
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