Digital Electronics - Counters - Discussion
Discussion Forum : Counters - General Questions (Q.No. 1)
1.
How many flip-flops are required to make a MOD-32 binary counter?
Discussion:
26 comments Page 2 of 3.
Neelima said:
1 decade ago
N <= 2^n.
Where N is modulus of counter.
n is no.of flip flops.
So when n=5 condition is satisfied.
Where N is modulus of counter.
n is no.of flip flops.
So when n=5 condition is satisfied.
Neha said:
1 decade ago
5 flip flops will be required if we count from 0 to 31 for mod 32 we will need 6 flip flops.
Komal jadhav said:
2 years ago
How many flip flops are required to design the mod 29 counter? Please explain to me.
Daniel said:
8 years ago
What is the least number of jk flip flops it would take to create a mod 500 counter?
SAMPATH said:
1 decade ago
How can you people say that and represent no of flip flops ? CAN anybody explain it?
T.Milhaan said:
1 decade ago
2^n>N>2^n-1
n-number of flip flops
N-number of states ie in mod32 N=32
n-number of flip flops
N-number of states ie in mod32 N=32
Ashwin said:
1 decade ago
Mod-32 means divide by 32 counter.
2^n=32. => n=5.
i.e. 5 flip flops.
2^n=32. => n=5.
i.e. 5 flip flops.
Gopi said:
1 decade ago
Mod-32 means divide by 32 counter.
2^n=32. => n=5.
i.e 5 flip flops.
2^n=32. => n=5.
i.e 5 flip flops.
Faisal yusuf said:
5 years ago
One flip flop store 1 bit 32 =100000 6 binary bit.
So, 6 flipflop use.
So, 6 flipflop use.
Niraj sharma said:
9 years ago
32 mod means till 5 digit number.
So 5 flip flop is required.
So 5 flip flop is required.
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