Database - The Relational Model and Normalization - Discussion
Discussion Forum : The Relational Model and Normalization - General Questions (Q.No. 1)
1.
Every time attribute A appears, it is matched with the same value of attribute B, but not the same value of attribute C. Therefore, it is true that:
Discussion:
23 comments Page 2 of 3.
Kash said:
1 decade ago
It is a general thing to be noticed that if A will be related to both B & C, then how can the value not be same to C. So option A is correct. !
ShivaKavya said:
1 decade ago
Because A can uniquely identifies B each time.
So A->B. Option A.
So A->B. Option A.
Abhishek tamrakar said:
1 decade ago
Beacause only value of A will match with B.
So A->B is true.
So A->B is true.
Richa Chaurasia said:
1 decade ago
Because of every attribute of A will also match with B but not C.
And then value of A $ B will depend to each other.
A->B.
And then value of A $ B will depend to each other.
A->B.
Vishnu said:
1 decade ago
The functional dependency A->B states that the set of values present in A are also in the B so that's why it matches the values in the case of A and B but not with C.
NiviKPR said:
1 decade ago
As per the rule A->B means if A is true then B is true.
Khalid seid said:
1 decade ago
Value of B depends on value of A. i.e A is the determinant but B is the dependent.
Ouen said:
1 decade ago
Value of B depends on value of A; i.e. A is uniquely determined B
CHANDRA said:
1 decade ago
A->B every attribute in A should match with B.
Runa said:
1 decade ago
A->B means the occurence of A attribute with B eyery time.
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