C++ Programming - OOPS Concepts - Discussion

Discussion Forum : OOPS Concepts - General Questions (Q.No. 38)

OOPS Concepts

38.

What happens if the base and derived class contains definition of a function with same prototype?

Compiler reports an error on compilation.

Only base class function will get called irrespective of object.

Only derived class function will get called irrespective of object.

Base class object will call base class function and derived class object will call derived class function.

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

22 comments Page 2 of 3.

Pallavi said: 1 decade ago

We can declare both base & derived class objects and as per that we can directly call the functions of that class.

Pooja said: 1 decade ago

It will raised an ambiguity error cause compiler will confused when we create the object of derived class.

Swapnil said: 8 years ago

If virtual not used so only baser class function is called. If virtual keyword used so both can be called.

Yogita said: 1 decade ago

I also agree with option B because both class contain same prototype. Prefrence gives to base class.

Dhanesh ful said: 1 decade ago

This example of method overrding only the the method of derived class is call istead of base class.

Ramanagarjuna R K said: 9 years ago

Yes, only base class function will be invoked irrespective of an object.

So, the answer is B.

Vishal Tavande said: 1 decade ago

Only base class function will get called irrespective of object. As I tried this at my desk.

Sona said: 1 decade ago

The answer given is right as it totally depends on calling class object.

Mangesh said: 9 years ago

D option is correct without doubt. I agree with the given answer.

Anisha said: 9 years ago

Yes, it's B. Agree with the above explanation.

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