C++ Programming - OOPS Concepts - Discussion

Friend constructor is not a type of constructor.

class Y
{
public:
Y();
};
class X
{
private:
void foo() {}
friend Y::Y();
};
Y::Y()
{
X x; x.foo();
}

As per 11.3 Friends [class.friend]


When a friend declaration refers to an overloaded name or operator, only the function specified by the parameter types becomes a friend. A member function of a class X can be a friend of a class Y.

[ Example:

class Y {
friend char* X::foo(int);
friend X::X(char); // constructors can be friends
friend X::~X(); // destructors can be friends
};

"end example ]

Because Constructor has three types:

1. Default Constructor.
2. Parameterized Constructor.
3. Copy Constructor.

The friend is not a type of any constructor. Right? If not please explain in detail.

Parameterized constructor is just like default constructor but allows the parameters just like functions with parameters.

Friend is not a constructor. It is just a function. All options except friend are types of constructor.

Friend is a function but it is not a constructor.

Friend Keyword is used for class and Functions. Rest of the 3 options are available constructor in c++.

Because friend function is used not constructor.

Friend is not a constructor its a function.

Remaining all option to be under the constructor type.

Constructor is used to invoke the object.