C++ Programming - Objects and Classes - Discussion
Discussion Forum : Objects and Classes - Programs (Q.No. 4)
4.
What will be the output of the following program?
#include<iostream.h>
class BixTeam
{
int x, y;
public:
BixTeam(int xx)
{
x = ++xx;
}
void Display()
{
cout<< --x << " ";
}
};
int main()
{
BixTeam objBT(45);
objBT.Display();
int *p = (int*)&objBT;
*p = 23;
objBT.Display();
return 0;
}Discussion:
13 comments Page 2 of 2.
Mehul said:
8 years ago
Here, int *p =(int *)&objBT;
this is type casting and a class pointer is temporary converted into (int* )type and p is now pointing to object the first member and we have modified that location so data is change accordingly.
this is type casting and a class pointer is temporary converted into (int* )type and p is now pointing to object the first member and we have modified that location so data is change accordingly.
Prashant said:
6 years ago
In case if more than 1 variable is there in class than how the pointer will work to initialize the value? please explain me.
Ashish Sharma said:
2 years ago
Here, know about the conversion constructor, which gets automatically called in some specific situations.
int *p = (int*)&objBT;
*p = 23;
In above-mentioned code, it will get called and assigned a value 23 to x.
int *p = (int*)&objBT;
*p = 23;
In above-mentioned code, it will get called and assigned a value 23 to x.
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