C++ Programming - Objects and Classes - Discussion

Yes, but this is not structure please explain in detail.

It's all about logical assignments.

y = x = (x = 4*4);

// Successful assignment " x=4*4 " returns.
// value 1 to x, in turn successful assignment " x = (...) ".
// returns value 1 to y, so y = 1; next.

y = --y * y; // --y is operated 1st so y = 0 now, then 0*0 = 0.

The void function was not called only display is invoked ? then how initialized y=x=(x=4*4).

How you say y=x=(x=4*4) is equal to 1?

In this example, we are not calling function Function(). So, value of y & x are not changed that's why it's displaying 0.

In above example, immediate to classes declarations, objects I and B are also constructed in global space so that I.B.Display() will give value any of its member initialized to default i.e here y is 0.

Note 1: By keeping declaration in global space and try to create objects I and B inside main() then I.B.Display() will give any of its member value as Garbage.

Note 1: Inside main(), declare class as static and then create objects also, in this case I.B.Display() will give value any of its member initialized to default i.e here y is 0.


#include <iostream>
using namespace std;

class Bix
{
int x;
float y;
public:
void Display()
{
cout<< y << endl;
}
}B;

int main()
{
static class Bbb
{
int x;
float y;
public:
void Display()
{
cout<< y << endl;
}
}Bb;

Bix B1;
B.Display();
B1.Display();
Bb.Display();
return 0;
}

Why answer is zero? How the function is evaluated?

Since argument type of function is void therefore it takes no arguments. Hence answer is zero.

y = x = (x = 4*4).

Explain above in details.

x = 4*4 = 16?

How could it 1?

What is the B and L in this program?

How the output will be zero?

Not understand please explain it.