C++ Programming - Objects and Classes - Discussion

We can't use * as pointer in CPP but instead of this we can use reference keyword.

Linker not able to find the definition for static function so throwing an an error. Not having a definition is not a semantic error so compiler was not finding it.

void(*ptr)() = &Bix::MyFunction;

What this line do?

:: what does this operator do?

:: this is a scope resolution operator. The scope resolution operator helps to identify and specify the context to which an identifier refers, particularly by specifying a namespace.

What is mean by linker error?

Linker Error because when the compiler is searching for the original function to link to at void (*ptr)() = &Bix::MyFunction; it cannot find it. because the function is not defined.
this below example works perfectly:
#include<iostream>
using namespace std;
class Bix
{
public:
static void MyFunction();
};
int main()
{
void (*ptr)() = &Bix::MyFunction;
(*ptr)();
return 0;
}
void Bix::MyFunction(){

cout<<"yay"<<endl;
}

Linker error because there is no function definition for MyFunction().

The linker error comes because the class is only declared and the definition is not there for the static member function.

If we give a definition for member function then the linker error will be resolved by adding the following code.

void Bix::MyFunction()
{
std::cout << "I am a static function of Class Bix"
}