Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 2 (Q.No. 41)
41.
With an IP address set starting with 150, you currently have six offices that you are treating as subnets. Plans are in place to open 10 more offices before the end of the year. What subnet mask should you use to satisfy the needed number of subnets and maximize the number of hosts available at each site?
Discussion:
18 comments Page 2 of 2.
Frank said:
8 years ago
How we get 240? Please explain.
Rashmi Vyas said:
8 years ago
Yes, the answer should be 240. I agree.
Rashmi vyas said:
8 years ago
Here, We need 16 subnets which can be represented as 2^4 so 4 bits are needed for subnet. Remaining bits can be used for hosts.
So, 11110000 = 128 + 64 + 32 + 16 = 240. Hence 240 should be the answer.
So, 11110000 = 128 + 64 + 32 + 16 = 240. Hence 240 should be the answer.
(1)
ADITHYA said:
7 years ago
10 + 6 = 16 and 16 + 2 = 18. On what basis 6 and 2 are taken?
V r Reddy said:
5 years ago
I too agree 240 is correct.
(1)
Varinderjit said:
5 years ago
The correct Answer is 240.
(1)
Patty said:
3 years ago
6 + 10 = 16 subnets.
Then 2^n>=x, where n=borrowed bits and x is the number of subnets.
What exponent to 2 and get 16.
2^4>=16, then the borrowed bits from host portion is 4, then in standard subnetting table 4 bits match to 240,
Then the answer is 240, not 248.
Then 2^n>=x, where n=borrowed bits and x is the number of subnets.
What exponent to 2 and get 16.
2^4>=16, then the borrowed bits from host portion is 4, then in standard subnetting table 4 bits match to 240,
Then the answer is 240, not 248.
(2)
Patty said:
3 years ago
Agree, C is the correct answer.
(1)
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