Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 1 (Q.No. 6)
6.
You have a class A network address 10.0.0.0 with 40 subnets, but are required to add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should you assign?
Discussion:
25 comments Page 2 of 3.
Daniel Asnakew said:
1 decade ago
In class a number of host are 3. The first host are divided in number of host so total host are 100 in binary form 1100100.
There are 7 bit it implies that 7 bit (1's). So11111111.11111110.00000000.00000000.
There are 7 bit it implies that 7 bit (1's). So11111111.11111110.00000000.00000000.
Qaim Khan nd wanted Bhai said:
10 years ago
What is computer network?
Sidharth said:
10 years ago
Please explain me how to calculate & how the answer is 255.254.0.0?
Santaji said:
9 years ago
Can anyone help me to solve this example?
Define the subnet mask to be used in Class-B addressing to support 30 subnet and also find the most possible in each subnet?
Define the subnet mask to be used in Class-B addressing to support 30 subnet and also find the most possible in each subnet?
Harish said:
9 years ago
First of all, we should know what is subnetting -it is a process in which we decide the subnet mask into parts and for that purpose, we have to convert last bit of network(1's) id in to host(0"s) id.
11111111 11111111 00000000 00000000
After converting.
11111111 11111110 00000000 00000000
11111111 11111111 00000000 00000000
After converting.
11111111 11111110 00000000 00000000
Sanjeevini said:
9 years ago
Can anyone help me how to solve this problem?
Sense said:
9 years ago
2^n = Number of Subnets where n is the number of masked on (1) bits in the subnet mask
now a number of Subnets are 60 + 40 = 100.
So, 2^n = 100, solving for n = log 100 /log 2
n=6.6 approximately n = 7
Thus Since the network address is in Class A, so the subnet bits will be in The 2nd eight bits of IP address with 7on bits and 1off bits.
The 1st eight bits will be all on.i.e 11111111 or 255, the 2nd eight bits will be 111111110 or 254 the rest will be 0's.
So the answer will be 255.254.0.0 subnet mask or D.
now a number of Subnets are 60 + 40 = 100.
So, 2^n = 100, solving for n = log 100 /log 2
n=6.6 approximately n = 7
Thus Since the network address is in Class A, so the subnet bits will be in The 2nd eight bits of IP address with 7on bits and 1off bits.
The 1st eight bits will be all on.i.e 11111111 or 255, the 2nd eight bits will be 111111110 or 254 the rest will be 0's.
So the answer will be 255.254.0.0 subnet mask or D.
(1)
GEREMEW BELACHEW said:
9 years ago
Very good. Thanks for all your explanation of the answer.
Lekha said:
9 years ago
(The no of host per subnet are 2^17 - 2 = 131070 (no of 0's are 17))
Can you explain this?
Can you explain this?
Sumana said:
8 years ago
Thanks for the explanation.
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