Computer Science - Networking - Discussion

Discussion Forum : Networking - Section 1 (Q.No. 42)
42.
With an IP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts?
192
224
240
248
252
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
18 comments Page 2 of 2.

DIPANJAN said:   10 years ago
What is meant by an IP Address of 100?

Does it means The IP Address is 100.0.0.0?

And if it is so, then in order to have 80 subnets we need 7 additional bits, and in that case the subnet mask would be 255.254.0.0.

But if it is CLASS LESS addressing, then we can count the 7 bits required for 80 subnets starting from the LSB of the first octave and in that case the required subnet mask would be 255.252.0.0.

Mearg said:   10 years ago
2^7= 128 ~= 80, we borrow 7 bis the result is 254.

Raj gopal said:   1 decade ago
I think the right answer is 254 but not 252. Since 80 lies between 2^6 = 64 and 2^7 = 128. Now when 7 bits are borrowed we will have subnet mask as 255.254.0.0 but not 255.252.0.0.

Computer nerd said:   1 decade ago
Max number will be for .192. Please check.

Sabitamohanty said:   1 decade ago
252 mask gives only 4 ip addresses, among 4 first is allocated to network and last to Broadcast, remain 2 valid IP addresses. Could anyone describe how it could be maximized the number of available hosts.

Vimy Sarcar said:   1 decade ago
Total Availble 254 Subnet Now One IP reduce is 100 Now Its 253 And One Router Also Reduce So Available 252.

Satyanarayana t said:   1 decade ago
What is the procedure to find it ?

Navjot said:   1 decade ago
Please add the description for this calculation


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