Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 1 (Q.No. 42)
42.
With an IP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts?
Discussion:
18 comments Page 2 of 2.
Mearg said:
10 years ago
2^7= 128 ~= 80, we borrow 7 bis the result is 254.
Raj gopal said:
1 decade ago
I think the right answer is 254 but not 252. Since 80 lies between 2^6 = 64 and 2^7 = 128. Now when 7 bits are borrowed we will have subnet mask as 255.254.0.0 but not 255.252.0.0.
Computer nerd said:
1 decade ago
Max number will be for .192. Please check.
Sabitamohanty said:
1 decade ago
252 mask gives only 4 ip addresses, among 4 first is allocated to network and last to Broadcast, remain 2 valid IP addresses. Could anyone describe how it could be maximized the number of available hosts.
Vimy Sarcar said:
1 decade ago
Total Availble 254 Subnet Now One IP reduce is 100 Now Its 253 And One Router Also Reduce So Available 252.
Satyanarayana t said:
1 decade ago
What is the procedure to find it ?
Navjot said:
1 decade ago
Please add the description for this calculation
Tejas said:
1 decade ago
How it is possible?
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