Computer Science - Networking - Discussion
Discussion Forum : Networking - Section 2 (Q.No. 33)
33.
You are working with a network that has the network ID 192.168.10.0. What subnet should you use that supports up to 25 hosts and a maximum number of subnets?
Discussion:
14 comments Page 2 of 2.
Tharindu said:
7 years ago
B is correct.
It is about subnet @Sibasish.
It is about subnet @Sibasish.
Gee said:
7 years ago
Please, anyone,explain the correct answer.
Kaa said:
5 years ago
The formula for finding the host is 2n (where n indicates the number of host bits)
We required 5 host bits (2n = 25) = 32
Now, let's find the subnet mask.
Hence, 5 bits are reserved for the host. There are 3 bits remaining for the network. Count the value of all the remaining three bits (27 + 26 + 25 = 224).
Therefore, the new subnet mask you will get is 255.255.255.224.
We required 5 host bits (2n = 25) = 32
Now, let's find the subnet mask.
Hence, 5 bits are reserved for the host. There are 3 bits remaining for the network. Count the value of all the remaining three bits (27 + 26 + 25 = 224).
Therefore, the new subnet mask you will get is 255.255.255.224.
Patty said:
3 years ago
B is correct.
2^n-2> = number of host.
2^n-2> = 25 then what number exponent to 2 and near reach of 25 or above
2^5-2> = 25 were 5 match is remaining host bits on host portion, then the borrowed bits from host portion are 3bits...then 3 bits match to 224 in binary ..11100000 last 0 take 0, second 0 from 1, p to n 0 then take 2^5+2^6+2^7 = 224.
2^n-2> = number of host.
2^n-2> = 25 then what number exponent to 2 and near reach of 25 or above
2^5-2> = 25 were 5 match is remaining host bits on host portion, then the borrowed bits from host portion are 3bits...then 3 bits match to 224 in binary ..11100000 last 0 take 0, second 0 from 1, p to n 0 then take 2^5+2^6+2^7 = 224.
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