Computer Science - Networking - Discussion
Discussion Forum : Networking  - Section 2 (Q.No. 40)
                   
                                       
                                40.
You are working with three networks that have the network IDs 192.168.5.0, 192.168.6.0, and 192.168.7.0. What subnet mask can you use to combine these addresses into one?
 
                                    Discussion:
13 comments Page 2 of 2.
                
                        Rahmat said: 
                         
                        4 years ago
                
                D is correct, as default subnet mask for class C is 255.255.255. , as 3 hosts are required, hence 252 is used.
                
                        Wasim sajjad said: 
                         
                        4 years ago
                
                11000000.10101000.00000101.000000 00 (192.168.5.0) =255.255.255.255-3.
11000000.10101000.00000110.000000 00 (192.168.6.0) = 255.255.255.255-3.
11000000.10101000.00000111.000000 00 (192.168.7.0). = 255.255.255.255-3.
                11000000.10101000.00000110.000000 00 (192.168.6.0) = 255.255.255.255-3.
11000000.10101000.00000111.000000 00 (192.168.7.0). = 255.255.255.255-3.
                        Ekta said: 
                         
                        3 years ago
                
                Agree, Option A is correct.
                Post your comments here:
 
            
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