Computer Science - Computer Fundamentals - Discussion
Discussion Forum : Computer Fundamentals - Section 17 (Q.No. 3)
3.
Multiplication of 1112 by 1012 is
Discussion:
13 comments Page 2 of 2.
Aswathy said:
8 years ago
111->7
101->5
7*5=35
35/2=17 --------------> 35%2=1
17/2=8 --------------> 17%2=1
8/2=4 --------------> 8%2=0
4/2=2 --------------> 4%2=0
2/2=1 --------------> 2%2=0
--------------> 1%2=1
Reading in reverse order we get the answer 100011.
101->5
7*5=35
35/2=17 --------------> 35%2=1
17/2=8 --------------> 17%2=1
8/2=4 --------------> 8%2=0
4/2=2 --------------> 4%2=0
2/2=1 --------------> 2%2=0
--------------> 1%2=1
Reading in reverse order we get the answer 100011.
(1)
Anirudh said:
7 years ago
111 in decimal is 7 and 101 in decimal is 5.
now multiply 7 and 5 ie. 7*5=35.
Next, convert 35 into binary by using 32-bit representation.
32 16 8 4 2 1.
1 0 0 0 0 1 (32+2+1=35 so put 1 in place of 32,2,1 and 0 in remaining places).
now multiply 7 and 5 ie. 7*5=35.
Next, convert 35 into binary by using 32-bit representation.
32 16 8 4 2 1.
1 0 0 0 0 1 (32+2+1=35 so put 1 in place of 32,2,1 and 0 in remaining places).
Muhammad Asif said:
6 years ago
7 = 111.
5 = 101.
So simple 5*7 = 35.
Now it will be convert in binary
32 16 8 4 2 1
1 0 0 0 1 1
35=100011.
The same technique will be used if large no occur.
5 = 101.
So simple 5*7 = 35.
Now it will be convert in binary
32 16 8 4 2 1
1 0 0 0 1 1
35=100011.
The same technique will be used if large no occur.
(2)
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