Computer Science - Computer Fundamentals - Discussion
Discussion Forum : Computer Fundamentals - Section 17 (Q.No. 3)
3.
Multiplication of 1112 by 1012 is
Discussion:
13 comments Page 2 of 2.
Mamatha said:
1 decade ago
111 --> 7
=> (2^0*1)+(2^1*1)+(2^2*1)
=>(1*1)+(2*1)+(4*1)
=>1+2+4
=>7
Same for 101
try it.
=> (2^0*1)+(2^1*1)+(2^2*1)
=>(1*1)+(2*1)+(4*1)
=>1+2+4
=>7
Same for 101
try it.
Sundar said:
1 decade ago
I have a simple idea to solve this kind of problem.
111 --> 7
101 --> 5
7 x 5 = 35
35 --> 100011 is the required answer.
111 --> 7
101 --> 5
7 x 5 = 35
35 --> 100011 is the required answer.
Sachin said:
1 decade ago
Explanation this question.
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