Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 4 (Q.No. 6)
6.
3.0 ml of raw sewage is diluted to 300 ml. The D.O. concentration of the diluted sample at the beginning of the test was 8 mg/l. After 5 day-incubation at 20°C, the DO. concentration was 5 mg/l. The BOD of raw sewerage is
Discussion:
12 comments Page 2 of 2.
Mahi said:
8 years ago
Thank you @Praveen.
Praveen kumar said:
1 decade ago
At first.
Bod = 8*(300/3) = 800.
2nd:
Bod = 5*(300/3) = 500.
Now 800-500 = 300mg/l.
Bod = 8*(300/3) = 800.
2nd:
Bod = 5*(300/3) = 500.
Now 800-500 = 300mg/l.
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