Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 5 (Q.No. 44)
44.
The width of a settling tank with 2 hour detention period for treating sewage 378 cu m per hour, is
Discussion:
14 comments Page 2 of 2.
Jinish said:
6 years ago
Depth of settling tank should d = 3 meter, not 4 meter and lenght= 4 times width, volume = q*t = 378*2.
So the width comes = 7.93.
So the width comes = 7.93.
(1)
Lalit pathade said:
6 years ago
Q = Volume/Time.
L = 4B, D=4m.
Q = LBH/Time.
378= 4B*B*4/2.
B = 6.87m~7m.
L = 4B, D=4m.
Q = LBH/Time.
378= 4B*B*4/2.
B = 6.87m~7m.
(5)
Dheeraj kataria said:
6 years ago
@Lalit you are right. And @Naveen You are wrong.
This is not a formula that you are solving the question.
The original formula is:
Detention time(dt) = volume(Lxbxh)/Discharge(Q).
This is not a formula that you are solving the question.
The original formula is:
Detention time(dt) = volume(Lxbxh)/Discharge(Q).
(1)
Anirban Roy said:
5 years ago
For Sedimentation tank :- l:b= 4 and b:d=2.
Vol=V= 378*2=756.
So, l*b*d= 756.
4b*b*(b/2)= 756; b= 7.23m ~ 7m.
Vol=V= 378*2=756.
So, l*b*d= 756.
4b*b*(b/2)= 756; b= 7.23m ~ 7m.
(4)
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