Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 1 (Q.No. 10)
10.
The width of a rectangular sewer is twice its depth while discharging 1.5 m/sec. The width of the sewer is
Discussion:
30 comments Page 2 of 3.
Saeed said:
4 years ago
Min v = 0.45.
b= 2d,
q = AV.
1.5 = b*d *0.45.
1.5= 2d*d*0.45 ,,d^2=1.5/0.9= 1.36.
d=1.36.
b= 2d,
q = AV.
1.5 = b*d *0.45.
1.5= 2d*d*0.45 ,,d^2=1.5/0.9= 1.36.
d=1.36.
(17)
Kranthi said:
9 years ago
I think the given question is wrong.
Because units of discharge is cubic meter per sec.
Because units of discharge is cubic meter per sec.
SHAH NAWAZ KHAN said:
8 years ago
Kindly help me,
If ::h = 0.88 then by width= 2h, it becomes equal to = 1.76.
If ::h = 0.88 then by width= 2h, it becomes equal to = 1.76.
(1)
Suresh said:
9 years ago
What are the units of discharge?
Can you verify that once in question?
Can you verify that once in question?
Gurjant singh said:
4 years ago
@Saeed.
It's the value of d square. So, the answer given is correct.
It's the value of d square. So, the answer given is correct.
(2)
Jinz said:
6 years ago
Isn't Q supposed to be in m^3/sec?
In question, it's given 1.5 m/sec.
In question, it's given 1.5 m/sec.
(4)
Gopal lal kumawat said:
8 years ago
What is the typical slope of a waste pipe?
A. 4%, B.3%, C.2%, D.1%
A. 4%, B.3%, C.2%, D.1%
Sadanand said:
9 years ago
It means we have to design the sewer for high velocity.
Monika Thakur said:
6 years ago
According to me, it is (Q/v) = 1.5 * 0.9 = 1.35.
Lea said:
8 years ago
@Roy
Te answer is 1.76 because of 0.88x2=1.76.
Te answer is 1.76 because of 0.88x2=1.76.
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