Civil Engineering - Waste Water Engineering - Discussion
Discussion Forum : Waste Water Engineering - Section 1 (Q.No. 10)
10.
The width of a rectangular sewer is twice its depth while discharging 1.5 m/sec. The width of the sewer is
Discussion:
30 comments Page 2 of 3.
SHAH NAWAZ KHAN said:
8 years ago
Kindly help me,
If ::h = 0.88 then by width= 2h, it becomes equal to = 1.76.
If ::h = 0.88 then by width= 2h, it becomes equal to = 1.76.
(1)
Monika Thakur said:
6 years ago
According to me, it is (Q/v) = 1.5 * 0.9 = 1.35.
Lakha said:
1 decade ago
For sewer velocity is 0.9m/sec to 0.75. So Q = AV.
Given b =2d and Q = 1.5.
Then A = Q/v, bd = 1.5/0.9 = 1.67.
(2d)d = 1.67, d = 0.91.
Hence b = 2(0.91) = 1.82 m.
Given b =2d and Q = 1.5.
Then A = Q/v, bd = 1.5/0.9 = 1.67.
(2d)d = 1.67, d = 0.91.
Hence b = 2(0.91) = 1.82 m.
PREM ROSHAN said:
3 years ago
@Gopal Lal Kumawat.
2% is the right answer.
2% is the right answer.
Emad Ernest Sadek said:
1 decade ago
Answer depends on velocity which is not given.
DHAWAL KALRA said:
1 decade ago
Here we can't assume the velocity direct as designing of sewer relates to max and min conditions of flow.
Rajmohan said:
10 years ago
I think they have to give slope of channel & manning constant then only we can approach to solve.
Sadanand said:
9 years ago
It means we have to design the sewer for high velocity.
Suresh said:
9 years ago
What are the units of discharge?
Can you verify that once in question?
Can you verify that once in question?
Kranthi said:
9 years ago
I think the given question is wrong.
Because units of discharge is cubic meter per sec.
Because units of discharge is cubic meter per sec.
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