Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 3)
3.
A horizontal rod AB carries three loads of 3.0 kg, 7.0 kg and 10.0 kg at distances of 2.0 cm, 9.0 cm and 15 cm respectively from A where it is hinged. Neglecting the weight of the rod, which is the point at which the rod will be balance ?
Discussion:
16 comments Page 2 of 2.
Abdul Khan said:
10 years ago
No one has considered the moment of A reaction, please elaborate I didn't understood.
(1)
Balaraju dasarla said:
9 years ago
Balanced distance = summation of moments/summation of loads.
d = 219/20,
= 10.95.
d = 219/20,
= 10.95.
Ateeq said:
10 years ago
Eccentric = Total moment at A/Total loads = 3*2+7*9+10*15 = 219/20 = 10.95 cm.
Rahul jain said:
9 years ago
@Abdul Khan.
Point A is hinged that's why the moment about A is zero.
Point A is hinged that's why the moment about A is zero.
Ashok said:
8 years ago
At hinge point moment is zero. What is the reaction on that point?
Habibur Rahman said:
4 years ago
3*2 + 7*9 + 10*15 = 20X.
Then, X = 10.95.
Then, X = 10.95.
(3)
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