Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 3)
3.
A horizontal rod AB carries three loads of 3.0 kg, 7.0 kg and 10.0 kg at distances of 2.0 cm, 9.0 cm and 15 cm respectively from A where it is hinged. Neglecting the weight of the rod, which is the point at which the rod will be balance ?
Discussion:
16 comments Page 2 of 2.
Kannan G said:
8 years ago
The answer is 10.95 cm from A.
Explanation : The ratio of the moment about A to the total load.
Answer : 10.95cm.
Explanation : The ratio of the moment about A to the total load.
Answer : 10.95cm.
Anbarasan muthaiah AP/CIVIL STAR LION ENGINEERING said:
8 years ago
RESULTANT* FORCE DISTANCE OF RESULTANT ACT FROM SUPPORT = SUM OF MOMENT
R * x = M.
R = 3+7+10 = 20 KG.
SUM OF M ABOUT B = (3*2)+(7*9)+(10*15) =219 KG.cm.
219= 20x,
x = 219/20 = 10.95cm.
R * x = M.
R = 3+7+10 = 20 KG.
SUM OF M ABOUT B = (3*2)+(7*9)+(10*15) =219 KG.cm.
219= 20x,
x = 219/20 = 10.95cm.
(5)
Abdelhamid said:
8 years ago
That's not complex+> explanation/blanced point which the point have equlibrim eq sum of force equla 0 force * (x-dis) = zero.
Ashok said:
8 years ago
At hinge point moment is zero. What is the reaction on that point?
SHIVA KUMAR M N said:
4 years ago
Appy Varignon theorem at A, which states moment produced by the resultant force at any point is equal to the sum of the moment produced by the indivisual force at the same point.
Appy at A, we get 20x = 3 * 2 + 7 * 9 + 10 * 15.
20x = 219, Hence x=10.95cm.
Appy at A, we get 20x = 3 * 2 + 7 * 9 + 10 * 15.
20x = 219, Hence x=10.95cm.
(6)
Habibur Rahman said:
4 years ago
3*2 + 7*9 + 10*15 = 20X.
Then, X = 10.95.
Then, X = 10.95.
(3)
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