Civil Engineering - UPSC Civil Service Exam Questions - Discussion
Discussion Forum : UPSC Civil Service Exam Questions - Section 1 (Q.No. 7)
7.
A short column of external diameter D and internal diameter d, is subjected to a load W, with an eccentricity 'e', causing zero stress at an extreme fibre. Then the value of 'e' must be
Discussion:
12 comments Page 2 of 2.
Ashwani bhandari said:
7 years ago
We know that e = (Z/A).
Section modulus for circular column Z = πx(D4-d4)÷(32D),
Area A= πx(D2-d2)÷4.
We know the formula of;
(D4-d4) is (D2+d2)( D2-d2),
Then e = Z ÷ A,
We get;
e = (D2+d2)/(8D).
Section modulus for circular column Z = πx(D4-d4)÷(32D),
Area A= πx(D2-d2)÷4.
We know the formula of;
(D4-d4) is (D2+d2)( D2-d2),
Then e = Z ÷ A,
We get;
e = (D2+d2)/(8D).
PRAMOD KUMAR said:
7 years ago
@AFRID:
Z=I/y I= (π*D^4)/64 y=D/2 so Z = (π*D^3)/32 .
But as D-d cannot cancel out by D so the term remains same and only 64 cancelled out by 2 hence it is 32.
Z=I/y I= (π*D^4)/64 y=D/2 so Z = (π*D^3)/32 .
But as D-d cannot cancel out by D so the term remains same and only 64 cancelled out by 2 hence it is 32.
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