Civil Engineering - Theory of Structures - Discussion

I think it is (3*3) + 4- (3*4) = 0.

Since it is frame no of the internal loop is zero the reaction and the point where the load is acting like hinge then total indeterminacy is equal to external +internal.

External=number of reaction - equilibrium equation=6-3=3.
Internal=3c-rection realized by a hinge.

Here c=number of closed loop = 0.
Rr=reaction released by hinge = sum (m-1).

Here m is 3 and only one hinge so rr=3-1=2.
Internal indertminance =3*0-2=-2.

Total indeterminancy=3-2=1.

I think M+r-2j is used for Truss not for FRAME.

Degree of external indeterminacy = r - 3 = 6 - 3 = 3.
Degree of internal indeterminacy = m - (2j - 3) = 3 - (2*4 - 3) = -2,
Degree of static indeterminacy = External + Internal = 3 -2 = 1.

Alternatively,
Degree of static indeterminacy = (m + r) - 2j = (3 + 6) - 2 * 4 = 1.

For frame;
3(m-j)+r-c
Here,
m=3
J=4
r=6
C=2
Solving, degree of indeterminacy = q.