Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 8 (Q.No. 16)
16.
Correction per chain length of 100 links along a slope of α radians, is
Discussion:
25 comments Page 2 of 3.
Sammer said:
4 years ago
100 α2 is the correct answer.
Sandi said:
5 years ago
How? anyone explain.
Sajith ca said:
7 years ago
Please explain the answer.
Navern said:
1 decade ago
Would you explain?
Sameer sopori said:
7 years ago
ch= s(1-cosθ)
ch= s- s cosθ
ch= s - d
Because d= s. cosθ.
For example: s=100, slope angle 45 degree
d= 100 . 0.70710
d= 70.71 THIS IS THE CORRECTION OF SLOPE LENGTH.
ch= 100-70.71.
ch= 29.29.
Ch is the correction of measured slope distance due to slope;
d is the horizontal distance.
ch= s- s cosθ
ch= s - d
Because d= s. cosθ.
For example: s=100, slope angle 45 degree
d= 100 . 0.70710
d= 70.71 THIS IS THE CORRECTION OF SLOPE LENGTH.
ch= 100-70.71.
ch= 29.29.
Ch is the correction of measured slope distance due to slope;
d is the horizontal distance.
Sandeep singh said:
7 years ago
100a^2÷2 = 50a^2.
Er Bibek said:
7 years ago
I agree on @Garry and @Deepa.
It should be 50a^2.
It should be 50a^2.
Garry said:
8 years ago
Agree @ Deepa.
The answer should be 50 a^2.
The answer should be 50 a^2.
Deepa said:
8 years ago
@Md Shekhar.
Then it will be 50a^2, right?
Then it will be 50a^2, right?
MD Shekhar said:
8 years ago
Slope correction=h^2/2L;
where h=L*angle in radian(a),
Here L=100 links,
So, slope correction=100*a^2.
where h=L*angle in radian(a),
Here L=100 links,
So, slope correction=100*a^2.
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