Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 43)
43.
The region of the cross-section of a column in which compressive load may be applied without producing any tensile stress, is known as the core of the cross-section. In circular columns the radius of the core, is
Discussion:
13 comments Page 2 of 2.
Anuj said:
7 years ago
The answer is correct.
e<= d/8,
e<=2r/8,
e<=r/4.
That is one- quarter of the radius.
e<= d/8,
e<=2r/8,
e<=r/4.
That is one- quarter of the radius.
Ska said:
7 years ago
Ans is correct.
e<=z/A. Where z = (π*d^4/64+π*d^4/64)*2/d.
Because z = Izz perpendicular to the surface.
And A= π*d^4/4.
So, z/A= d/4.
e<=z/A. Where z = (π*d^4/64+π*d^4/64)*2/d.
Because z = Izz perpendicular to the surface.
And A= π*d^4/4.
So, z/A= d/4.
Rohit joshi said:
6 years ago
Dia of core section = d/4 or r/8.
Radius of core section = d/2 or r/4.
Radius of core section = d/2 or r/4.
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