Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 19)
19.
The ratio of the maximum deflections of a beam simply supported at its ends with an isolated central load and that of with a uniformly distributed load over its entire length, is
1
Discussion:
24 comments Page 2 of 3.
Prasanth said:
8 years ago
But some books said 5/8, they took udl deflection divided by point load deflection.
Mayuri said:
10 years ago
Ratio is 8/5, hence multiplying by 3 we will get 24/15 which is given in options.
Fakhar Naveed said:
1 year ago
It's correct.
384/48×5 = 384/ 240 = by dividing you will get the answer 24/15.
384/48×5 = 384/ 240 = by dividing you will get the answer 24/15.
(2)
Mekonnen S. said:
7 years ago
8/5 is the right answer.
Therefore, 8/5 * 3/3 = 24/15 is correct.
Therefore, 8/5 * 3/3 = 24/15 is correct.
Manoranjan said:
9 years ago
I am not getting this, Please, Properly discuss this question.
Indu said:
8 years ago
How 24/15 is correct, could you explain me please clearly?
Sanjeev kumar said:
9 years ago
Answer is 8/5. Why we need to multiply the factor 3?
Nikhil said:
8 years ago
24/15 is equal to 8/5 so 24/15 is correct answer.
Fakhar Navee said:
2 years ago
Here, it should be wl³/48EI × 384EI /5wl⁴ = 8/5.
Kallan said:
8 years ago
8/5 = 1.6,
24/15 = 1.6,
Both are same.
24/15 = 1.6,
Both are same.
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