Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 9)
9.
A steel rod of 2 cm diameter and 5 metres long is subjected to an axial pull of 3000 kg. If E = 2.1 x 106, the elongation of the rod will be
Discussion:
38 comments Page 4 of 4.
Hemanthkumar MS said:
9 years ago
It should be 2.275 mm.
Usha said:
9 years ago
I agree @Situ Gupta.
Akib khan said:
9 years ago
You are right @Situ Gupta.
Sachin said:
9 years ago
The correct answer is 2.27mm. Check the calculation once.
Sanjeev ranjan said:
9 years ago
I agree with your answer @Situ Gupta.
Situ gupta said:
9 years ago
A = 314.16 mm^2.
Elongation= Pl/AE.
= (3000 * 5 * 10^3)/(314.16 * 2.1 * 10^6).
= 0.02275 mm.
Elongation= Pl/AE.
= (3000 * 5 * 10^3)/(314.16 * 2.1 * 10^6).
= 0.02275 mm.
Gani said:
10 years ago
It should 2.2275 mm.
Prithveeraj said:
1 decade ago
Elongation = PL/AE.
= 3000*500/(2.1*10^6*3.14*2^2/4).
= 0.2275 mm.
= 3000*500/(2.1*10^6*3.14*2^2/4).
= 0.2275 mm.
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